If a-b 3 and a2+b2 29 find the value of ab
WebAnswer: Option A Solution (By Examveda Team) 2ab = (a 2 + b 2) - (a - b) 2 2ab = 29 - 9 2ab = 20 ∴ ab = 10 Join The Discussion * Related Questions on Simplification A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. WebClick here👆to get an answer to your question ️ If a + b = 5 and ab = 6 , then find a^2 + b^2 . Solve Study Textbooks Guides. Join / Login. Question . If a + b = 5 and a b = 6, then find a 2 + b 2. ... If a − b = 5 and a b = 1 2, find the value of …
If a-b 3 and a2+b2 29 find the value of ab
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WebIf a + b + c = 9, and a2+b2+c2 =35, find the value of a3+b3+c3−3abc. Q. If a3+b3+c3 =3abc and a+b+c=0, then find (b+c)2 3bc + (c+a)2 3ac + (a+b)2 3ab. Q. If a3 + b3 + c3 = 3abcanda+ b + c = 0. then (b + c)2 3bc + (c + a)2 3ac + (a + b)2 3ab = ? Q. If a+b+c=1;a2+b2+c2 =2;a3+b3+c3 =3, then. View More.
Web19 feb. 2024 · a-b = 3, or a^2–2ab+b^2 = 9 But a^2+b^2 = 29. So 29–9 = 20 = 2ab, or ab = 20/2 = 10. Answer. 132 views · Answer requested by Jyotsna Paryani Dipankar Goswami, B.E. Computer Science, Sardar Vallabhbhai National Institute of Technology, Surat (2006) Answered Feb 19, 2024 (a-b)^2 =a^2 +b^2 - 2ab => 3^2 = 29 - 2ab => 2ab = 29 - 3^2 => … WebAnswers (1) According to the problem given, a - b = 3 --- ( 1 ) a² + b² = 29---- ( 2 ) We know that the algebraic identity, ( a - b )² = a² + b² - 2ab. 3² = 29 - 2 ab. [ From ( 1 ) and ( 2 ) ] 9 = 29 - 2ab.
WebClick here👆to get an answer to your question ️ If a - b = 7 and a^3 - b^3 = 133, find: ab. Solve Study Textbooks Guides. Join / Login >> Class 9 >> Maths >> Polynomials ... If a − b = 6 and a b = 2 0, find the value of a 3 − b 3. Medium. View solution > View more. More From Chapter. Polynomials. View chapter > WebIf a - b = 3 and a 2 + b 2 = 29, find the value of ab. 10 12 15 18 Answer: Option Explanation: 2 ab = ( a 2 + b 2) - ( a - b) 2 = 29 - 9 = 20 ab = 10. Discussion: 106 comments Page 1 of 11. said: ...
WebGiven a+b =10so (a+b) 2=a 2+b 2+2ab 10 2=58+2ab ∴2ab=100−58=42 ∴ab=21 (a+b) 3=a 3+b 3+3ab(a+b) 10 3=a 3+b 3+3×21×10 ∴a 3+b 3=1000−630=370.
Weba + b = 3a - 3b 4b = 2a b = a/2 a+b =6 turns into a+ (a/2) = 6 multiply by 2, 2a+a=12 3a = 12 a = 4 since b = a/2 and a =4 then b=2. answer : a=4, b=2. More answers below Yash Dave Mathemagic 7 y Some Users have already answer it Here it is in different way a+b=6…. (1) a-b=2…. (2) Here coefficient of equation 1&2 will be the elements of determinate ks2 science backgroundWebIf a - b = 3 and a2 + b2 = 29, find the value of ab. Browse by Stream Login. QnA. Home. QnA. Engineering and Architecture; Computer Application and IT; Pharmacy; Hospitality and Tourism ... a - b = 3 ---( 1 ) a² + b² = 29----( 2 ) We know that the algebraic identity, ( a - b )² = a² + b² - 2ab. 3² = 29 - 2 ab [ From ( 1 ) and ( 2 ) ] 9 ... ks2 science dissolvingWebIf a - b = 3, a 2 + b 2 = 29, find the value of ab. Answer: A) 10 Explanation: 2ab= a 2 + b 2 - a 2 - b 2 29-9=20 =>ab=10 Subject: Simplification - Quantitative Aptitude - Arithmetic Ability Related Questions Q: If ( cos 2 θ - 1) ( 1 + tan 2 θ) + 2 tan 2 θ = 1, 0 ° < θ < 90 ° then θ is: View Answer Report Error Discuss ks2 science food chainsWebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. ks2 science activitiesWebGiven, a+b=10,a 2+b 2=58, then find a 3+b 3= A 340 B 370 C 390 D 410 Medium Solution Verified by Toppr Correct option is B) Given a+b =10 so (a+b) 2=a 2+b 2+2ab 10 … ks2 science day and nightWebLet , a+b=3——— (1) equation ab=2—— (2) equation Now take eq. 1 and find the value of b, b= (3-a). Put this value of b in the eq. (1) , a (3-a)=2 3a-a^2=2 a^2–3a+2=0, this is square equation so it has two value and when we factorized it we got, a^2–2a-a+2=0 a (a-2)-1 (a-2)=0 (a-1) (a-2)=0 ks2 science fictionWebAlgebra Simplify (a+b) (a^2-ab+b^2) (a + b) (a2 − ab + b2) ( a + b) ( a 2 - a b + b 2) Expand (a+b)(a2 −ab+b2) ( a + b) ( a 2 - a b + b 2) by multiplying each term in the first expression by each term in the second expression. a⋅a2 + a(−ab)+ab2 +ba2 +b(−ab)+b⋅b2 a ⋅ a 2 + a ( - a b) + a b 2 + b a 2 + b ( - a b) + b ⋅ b 2 Simplify terms. ks2 science framework